We began today's experiment by linearizing this graph and finding the voltage resolution to be .0196v after dividing by the ration of .5v/255. We then subtracted 25 degrees to 37 degrees to get 12 degrees. Then we used deltaV to figure out the temperature resolution.
Next we attempted to figure out the solution to Vout and had to redesign the circuit a couple of times. We tested 6.8 ohms and got 1.9V then 8.2ohms to get -2.15V.
In the end our quadratic equation came out with imaginary numbers meaning the requirements were not achievable so we had to change the requirements.
Here is the circuit we implemented which didn't work at first because there was no power being supplied from my laptop, but quickly finding the problem we switched to another laptop and it worked.
This is the voltage obtained for the 8.2 resistance.
This was our final exercise of the day. We learned about the ground symbol and how electrical currents can be dumped by the ground. We also learned about node voltage as seen below. Here we used KCL and converted everything to V/R to find the voltages V1 and V2.
No comments:
Post a Comment