Here we solved for the Maximum Power P=V^2/4(RL). We short the voltage and close the current to find RL.
Here we solved for the power of the circuit.
Here we used the chain rule and product rule to find RL=Rth.
On this circuit we solved for the power at different resistor values.
On this circuit we found the resistance of each battery in the circuit and found their equivalent resistance inverted and set that equal to Rth. Rth is.028 ohms and Vth is 24v. The power is 5052W(180)=909kJ we found the current to be 10.5 amp hours.
We graphed the power vs the resistance of a potentiometer in a circuit..
The table is shown below.
A zoomed version of the graph.
Our work done on the board for the graph.
Our results matched that of the professor.
Our work done for the exercise on this circuit solving for Rth and the voltage going out.
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